-7-9m+3m^2=2m^2-4m-9

Solution for -7-9m+3m^2=2m^2-4m-9 equation:

-7-9m+3m^2=2m^2-4m-9

We move all terms to the left:

-7-9m+3m^2-(2m^2-4m-9)=0

We get rid of parentheses

3m^2-2m^2-9m+4m+9-7=0

We add all the numbers together, and all the variables

m^2-5m+2=0

a = 1; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·1·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{17}}{2*1}=\frac{5-\sqrt{17}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{17}}{2*1}=\frac{5+\sqrt{17}}{2}
$